Calling my function? - Printable Version

Calling my function? - Printable Version

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Calling my function? - Jordy Clasie - Jun 10, 2013

Hey guy's so i created a function call nameString, with the parameter placeholder called (name)

When i put my own name in the parameter it give me the following error

ReferenceError: kevin is not defined, but i define the parameter when i am calling the function.

Code 
var nameString = function (name) {

    return "Hi, I am" + " " + name;

};

nameString = kevin;

console.log (nameString);

Could anyone please help me out, i am a JS beginner but i am still getting more the hang of it.

* - ๖ۣۜAlexander - Jun 10, 2013

Try calling the function like this:

Code 
nameString(keven)

OR

nameString("Keven")

Not sure with or without ", been a long time since I used JS.

* - Jordy Clasie - Jun 10, 2013

(Jun 10, 2013 10:07 AM)AnonGenReleases Wrote: Try calling the function like this:

Code
nameString(keven) OR nameString("Keven")

Not sure with or without ", been a long time since I used JS.

Thank's got it already and it is without the quotation marks.

* - Mafugsa Bob - Jun 10, 2013

Wrong section.

Web Development

@Anon

nameString("Keven"); is correct.

@OP

nameString = "Kevin"; should fix it. Otherwise it's looking for a variable called "Kevin"

PHP Code 


<?php 
var x = "I_am_a_string";
var I_am_a_string = x;
console.log(I_am_a_string); //I_am_a_string 

Works

PHP Code 


<?php 
var x = I_am_a_string;
console.log(x); 

Does not work. You'd get an error like: "ReferenceError: kevin is not defined".