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+---- Thread: [Python] Changing a part of a string, but still displaying the other part. (/showthread.php?tid=3746466)
Changing a part of a string, but still displaying the other part. - ๖ۣۜAlexander - Sep 10, 2013
So, I've got a bit stuck and I've found no answer.
What I actually want is something like this:
Code
Time left: 4
Time left: 3But I don't want the 'Time Left' to be printed everytime but just for the number (4) to change.
How can I do this with python? Or should I clear the screen everytime and reprint the string?
Cheers!
* - ßlack мesa - Sep 10, 2013
So, you want the console to print 'Time Left: n' on a single line and for the line to 'update' to the console with a new value for n?
Try this,
Code
import time, sys
for i in range(100):
time.sleep(1)
sys.stdout.write("\rTime Left:%d%%" %i)
sys.stdout.flush()* - PigBacon - Sep 10, 2013
If you're sneaky you can just print \d (the delete character) then print the correction.
* - Logicmorg - Sep 11, 2013
Does the entire thing have to be 1 string?
For example would this be acceptable:
PHP Code
<?php
import time
import sys
x = 100;
for i in range(0, 100):
time.sleep(1)
print("Time left: " + x);
x = x -1;
EDIT: Just realized this is wrong, x should be a string when being used by the function print. Since OP has said this script is not the one he is looking for please disregard this code.
* - ๖ۣۜAlexander - Sep 11, 2013
(Sep 11, 2013 06:49 AM)Logicmorg Wrote: Does the entire thing have to be 1 string?
For example would this be acceptable:
PHP Code
<?php
import time
import sys
x = 100;
for i in range(0, 100):
time.sleep(1)
print("Time left: " + x);
x = x -1;
That will just print the string over and over after a second.
Like this:
Code
Time left: 4
Time left: 3I don't want that. I just want the number to change but for the 'time left' to be on the same line.
* - MR.FREE - Sep 11, 2013
use string specifiers with a loop should handle that for you?
wait I see what your asking now...
* - Logicmorg - Sep 11, 2013
(Sep 11, 2013 07:39 AM)The Ð Wrote: That will just print the string over and over after a second.
Like this:
CodeTime left: 4
Time left: 3
I don't want that. I just want the number to change but for the 'time left' to be on the same line.
Okay I see what you are saying ( I think )
You want to display
Time left: 4
then after second goes by the 4 is then replaced with a 3, is this correct?
* - ๖ۣۜAlexander - Sep 11, 2013
(Sep 11, 2013 08:12 AM)Logicmorg Wrote: Okay I see what you are saying ( I think )
You want to display
Time left: 4
then after second goes by the 4 is then replaced with a 3, is this correct?
Yea, that's correct! All on the same line :)
* - kieranlav - Sep 11, 2013
There is a really simple method you could use if you wish.
Code
import time
for i in range(100):
time_left = 100 - i
time.sleep(1)
print("You have {0} seconds left.".format(time_left))This is not really a very good way about doing this but I though I should provide a way using very simple code. Not this is not the best or even a good way of doing this. Also this code is in python 3.x format.
--
Just took a look through the later parts of the thread and I see that this is not really what you want. I will try and think of a way to do what you want gimmie a sec.
* - ßlack мesa - Sep 11, 2013
(Sep 11, 2013 08:22 AM)The Ð Wrote: Yea, that's correct! All on the same line :)I did this for you earlier... Check at the top.
* - ๖ۣۜAlexander - Sep 11, 2013
(Sep 11, 2013 09:49 AM)ßlack мesa Wrote: I did this for you earlier... Check at the top.
I don't have access to pc now, so I'm just taking suggestions which I can use later when I'm on PC :)
* - kieranlav - Sep 11, 2013
(Sep 11, 2013 10:21 AM)The Ð Wrote: I don't have access to pc now, so I'm just taking suggestions which I can use later when I'm on PC :)
Code
import time
import sys
for i in range(4, 0, -1):
print('\rTime left:', i, end='')
sys.stdout.flush()
time.sleep(1)There you go, change the range accordingly. I would also like to note that this wont work in the idle I don't think. It should be ran how a user would run it.
Here is the version of the code for 2.x
Code
import time
import sys
for i in range(4, 0, -1):
print '\rTime left:', i,
sys.stdout.flush()
time.sleep(1)