Python [py challenge] challenge #1

[Python] [py challenge] challenge #1 - Printable Version

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[py challenge] challenge #1 - SupreemJuggalo - Dec 23, 2013

hey all, this is to test your python skills. (i hope you like them, if i get good feedback i will post more)

questions:

1. Write a function called hypotenuse that returns the length of the hypotenuse of a right triangle given the lengths of the two legs as arguments.

2. Write a function called circle_area that takes in two points (each with an x and a y value) which are the center of a circle and a point on the circumference of the circle and then calculates the area of that circle. An example of the function call would be:
Ex. circle_area(4,1,6,12)

post the source code in Pastebin or if you must you can use the "

Code 
and

" tags (code tags)

* - ImportUsername - Dec 23, 2013

I would hope that you're not using this for homework under the ruse of a challenge...
Spoiler (Click to View)

* - SupreemJuggalo - Dec 23, 2013

(Dec 23, 2013 01:38 PM)ImportUsername Wrote: I would hope that you're not using this for homework under the ruse of a challenge...
Spoiler (Click to View)
http://pastebin.com/f1HfGa4p

the second question you answered looks correct but the anser for the first one should look more like this

Code 
import math

def hypotenuse(a,b): #pythagorgas's theorem

    c=a**2+b**2

    hypo=math.sqrt(c) #square roots

    print(hypo)

#hypotenuse(3,4)

also, no its not for homework LOL, im not taking my python course this year.

* - ImportUsername - Dec 23, 2013

(Dec 23, 2013 01:58 PM)SupreemJuggalo Wrote: the second question you answered looks correct but the anser for the first one should look more like this

Code
import math def hypotenuse(a,b): #pythagorgas's theorem c=a**2+b**2 hypo=math.sqrt(c) #square roots print(hypo) #hypotenuse(3,4)

also, no its not for homework LOL, im not taking my python course this year.

Why would I calculate the hypotenuse by squaring each and then finding the square root of the sum when there is already a function to find the hypotenuse?

from the python docs (http://docs.python.org/2/library/math.html):
"math.hypot(x, y)
Return the Euclidean norm, sqrt(x*x + y*y)"

It's a waste of lines of code

Also the answer you gave is wrong according to your question. You say to make a function that "returns the length of the hypotenuse", but the one you gave as a correct answer only prints it

* - glob - Dec 23, 2013

Spoiler (Click to View)

* - Trolkar8 - Dec 24, 2013

Haha, I guess he is not very experienced with python...

* - Goodies - Dec 24, 2013

Here's mine:

PHP Code 


<?php 
import math #lel kinda cheating but not really
hypotenuse = lambda x, y:math.sqrt((x)**2 + (y)**2)
circle_area = lambda a, b, c, d:(((c-a) ** 2)+((d-b)**2)) * math.pi 

Did I do good?

* - DpzFAsq4UEK8 - Dec 24, 2013

Here's mine

PHP Code 


<?php 
#Hypotenuse
sqrt = lambda a:a**0.5
hypotenuse = lambda c,d:sqrt(((c**2)+(d**2))) 

PHP Code 


<?php 
#Circle
from math import pi,sqrt
circle_area = lambda e,f,g,h: pi*(sqrt((g-e)**2+(h-f)**2))**2 

(Dec 24, 2013 03:44 AM)Goodies Wrote: Here's mine:

PHP Code
<?php import math #lel kinda cheating but not really hypotenuse = lambda x, y:((x * x) + (y*y)) ** 2 circle_area = lambda a, b, c, d:(((c-a) ** 2)+((d-b)**2)) * math.pi

Did I do good?

Isn't square root the 1/2 power of a number?

* - ImportUsername - Dec 24, 2013

(Dec 24, 2013 04:00 AM)korn36 Wrote: Here's mine

PHP Code
<?php #Hypotenuse sqrt = lambda a:a**0.5 hypotenuse = lambda c,d:sqrt(((c**2)+(d**2)))

PHP Code
<?php #Circle from math import pi,sqrt circle_area = lambda e,f,g,h: pi*(sqrt((g-e)**2+(h-f)**2))**2

Isn't square root the 1/2 power of a number?

Yea Goodies is a bit off on his hypotenuse. For example with the one he gave, hypotenuse(3,4) returns 625 instead of 5. I guess that's what happens when you cheat cough cough

Also korn why do you make this:
sqrt = lambda a:a**0.5
when you could import sqrt from math?

* - DpzFAsq4UEK8 - Dec 24, 2013

(Dec 24, 2013 08:18 AM)ImportUsername Wrote: Yea Goodies is a bit off on his hypotenuse. For example with the one he gave, hypotenuse(3,4) returns 625 instead of 5. I guess that's what happens when you cheat cough cough

Also korn why do you make this:
sqrt = lambda a:a**0.5
when you could import sqrt from math?

I didn't want to use the math module on that one (and I know that sqrt is in math module...).
And on that second one I used math because I thought it would give me more precision for the pi number than assigning the pi variable manually.

* - Goodies - Dec 24, 2013

(Dec 24, 2013 08:18 AM)ImportUsername Wrote: Yea Goodies is a bit off on his hypotenuse. For example with the one he gave, hypotenuse(3,4) returns 625 instead of 5. I guess that's what happens when you cheat cough cough

Also korn why do you make this:
sqrt = lambda a:a**0.5
when you could import sqrt from math?

I didn't cheat lol I BORROWED. LOL
I'm not good with logic O.o

That's not the part of python I work with.

Eh... updated. Pretty sure it works now.