Python Beautiful Soup finding href

[Python] Beautiful Soup finding href - Printable Version

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Beautiful Soup finding href - IGotTheKeys - Aug 10, 2016

Hey, im trying to retrieve the 64 from this <a> tag.Could anyone tell me how to use the soup.find function in regards to finding a href and a class(in this case the "temp" class )

"<a href="THELINKWOULDGOHEREBUTICANTPOSTIT">London, United Kingdom64°</a>
"

Heres what ive tried:

data1 = [link['href'] for link in soup.findAll("a", {"class": "temp"})]
data1= soup.find('a', attrs={'class' : 'temp'}).find('a', href=True)

* - zmetra - Aug 10, 2016

(Aug 10, 2016 04:22 PM)IGotTheKeys Wrote: Hey, im trying to retrieve the 64 from this <a> tag.Could anyone tell me how to use the soup.find function in regards to finding a href and a class(in this case the "temp" class )

"<a href="THELINKWOULDGOHEREBUTICANTPOSTIT">London, United Kingdom64°</a>
"

Heres what ive tried:

data1 = [link['href'] for link in soup.findAll("a", {"class": "temp"})]
data1= soup.find('a', attrs={'class' : 'temp'}).find('a', href=True)

I'm not familiar with beautifulsoup, but you can use the re module.

Code 
# Removing the ''.join will output a tuple.

for data in re.findall('<a href="(.*?)">|<span class="temp">(\d+)&deg;', html):

    print(''.join(data))

Output:

Quote:THELINKWOULDGOHEREBUTICANTPOSTIT
64

* - Madathf - Aug 13, 2016

PHP Code 


<?php 
temp = soup.findAll('span', attrs = {"class" : "temp"})[0].string 

🤝

* - SIM-1866423 - Aug 13, 2016

PHP Code 

<?php 
import bs4

soup = bs4.BeautifulSoup('<a href="THELINKWOULDGOHEREBUTICANTPOSTIT">London, United Kingdom<span class="temp">64&deg;</span><span class="icon i-33-s"></span></a>',"html.parser")
print  (soup.find_all("span", class_="temp" )[0].contents[0])

Py3 not use findAll anymore be careful(https://www.crummy.com/software/BeautifulSoup/bs4/doc/).

* - Goodies - Aug 13, 2016

(Aug 10, 2016 05:19 PM)zmetra Wrote: I'm not familiar with beautifulsoup, but you can use the re module.

Code
# Removing the ''.join will output a tuple. for data in re.findall('<a href="(.*?)">|(\d+)°', html): print(''.join(data))

Output:

I love regex as much as the next guy, assuming the next guy also has nightmares about regex, but bs4 is the way to go for any html parsing project.