Python Python putting List within List when I only want one List

[Python] Python putting List within List when I only want one List - Printable Version

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Python putting List within List when I only want one List - Ineed2learn2eat - Jul 13, 2017

Im fetching a row from a table that has multiple values delimited by a ";". I'm trying to store it within a list. Everything works but instead of python printing it as just ['a','b','c']... it is printing it as [['a','b','c']].

Code below

Code 
cur.execute("SELECT * FROM Main_Setup");

rows = cur.fetchall()

job1= []

job2=[]

for row in rows:

    name = row[1]

    fields = row[4].split(';')

    if name == 'File1':

        job1.append(fields)

    elif name == 'file2':

        job2.append(fields)

Output

Code 
[['this field', '   another field']]

[['haha', 'no', '  yes']]

Desired Output

Code 
['this field', '   another field']

['haha', 'no', '  yes']

* - TheMarkMan - Jul 13, 2017

Try extending, not appending. That should work out
ex: job1.extend(fields)

* - datguy.dev - Jul 13, 2017

You're putting a list into an array... so that's what you'll get doing so. To access the elements you want, you'd have to use jobs2[0]. The len(jobs2) = 1. But len(jobs2[0]) == len(fields).

PHP Code 


<?php 
elif name == 'file2':
    for i in fields:
        job2.append(i) 

* - Ineed2learn2eat - Jul 13, 2017

(Jul 13, 2017 07:51 AM)TheMarkMan Wrote: Try extending, not appending. That should work out
ex: job1.extend(fields)

Extending worked! Thank you very much