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[Python] [solved]Pynput - capturing CTRL + C - Printable Version +- Hack Forums (https://hackforums.net) +-- Forum: Tech (https://hackforums.net/forumdisplay.php?fid=444) +--- Forum: Coding (https://hackforums.net/forumdisplay.php?fid=151) +---- Forum: Software Development (https://hackforums.net/forumdisplay.php?fid=118) +---- Thread: [Python] [solved]Pynput - capturing CTRL + C (/showthread.php?tid=5683147) |
[solved]Pynput - capturing CTRL + C - TheWarOwl - Jul 31, 2017 EDIT: The solution is to use key.name So assuming I use the example code: PHP Code When you press CTRL + C and release it, the release function outputs: '\x03' Which I believe is ascii for ctrl^c, which I could handle with a simple dictionary I believe. The issue is the keypress function gets this character: Which I can do nothing with... Anyone got any ideas on what I can do? EDIT: The documentation shows "Controller.modifiers" but not much on how it's used. I really hope this isn't a stupid question, I'm completely lost. * - _Pr0xy - Jul 31, 2017 What I did when I created my keylogger was figure out what ascii code was printed when that combination was used, so I don't know how reliable it is, but it looked similar to this: if key.char == "": string += "[CTRL-C]" This doesn't work for some combinations like CTRL-Z, but it does for CTRL-C and V EDIT: The ascii code isn't showing up but it is meant to be that icon for \x03 * - TheWarOwl - Jul 31, 2017 (Jul 31, 2017 01:36 PM)_Pr0xy Wrote: What I did when I created my keylogger was figure out what ascii code was printed when that combination was used, so I don't know how reliable it is, but it looked similar to this: Yes, that'd work with the keyrelease function, but it doesn't work with the keydown function... because the results are sometimes the same. Thank you though for the input 👍 |