(Jan 5, 2019 11:16 AM)_CASP3R_ Wrote:  Hello, I just thought id ask a question and see if anybody knows because ive been trying all day.

Basicly What i want to do is  launch a remote desktop connection and immediately hide it.
What i can already do to some extent. Basicly it hides the connecting window instead of the window when it connected.  I know its possible to do because i tested it with a button. but i wanna do it automatically.


Here is my code.

Code

private const int SW_HIDE = 0;
[DllImport("User32")]
private static extern int ShowWindow(int hwnd, int nCmdShow);


Process rdcProcess = new Process();
rdcProcess.StartInfo.FileName =
Environment.ExpandEnvironmentVariables(@"%SystemRoot%\system32\mstsc.exe");
rdcProcess.StartInfo.Arguments = "/v " + ""; //
rdcProcess.Start();

foreach (Process process in array)
{
  if (process.ProcessName == "mstsc")
  {
      int hWnd;
      hWnd = proccess.MainWindowHandle.ToInt32();
      ShowWindow(hWnd, 0);
  }
}

(Jan 5, 2019 11:37 AM)˗ˏˋ NYAN CAT ˎˊ˗ Wrote:  

PHP Code


<?php 
       Dim RDP As New ProcessStartInfo With {
        .FileName = "mstsc",
        .Arguments = "/v: 127.0.0.1",
        .WindowStyle = ProcessWindowStyle.Hidden
        }

        Process.Start(RDP) 


EDIT : sorry I thought it was VB section.

PHP Code


<?php 
   ProcessStartInfo RDP = new ProcessStartInfo()
    {
        FileName = "mstsc",
        Arguments = "/v: 127.0.0.1",
        WindowStyle = ProcessWindowStyle.Hidden
    };

    Process.Start(RDP); 


(Jan 5, 2019 11:37 AM)˗ˏˋ NYAN CAT ˎˊ˗ Wrote:  

PHP Code


<?php 
       Dim RDP As New ProcessStartInfo With {
        .FileName = "mstsc",
        .Arguments = "/v: 127.0.0.1",
        .WindowStyle = ProcessWindowStyle.Hidden
        }

        Process.Start(RDP) 


EDIT : sorry I thought it was VB section.

PHP Code


<?php 
   ProcessStartInfo RDP = new ProcessStartInfo()
    {
        FileName = "mstsc",
        Arguments = "/v: 127.0.0.1",
        WindowStyle = ProcessWindowStyle.Hidden
    };

    Process.Start(RDP); 


(Jan 5, 2019 11:41 AM)_CASP3R_ Wrote:  Bro. I fucking love you. Thank you so much. You dont understand what this means. TY

---

Hey man... Just tried the code. The window still appears.

(Jan 5, 2019 11:49 AM)Abruptum Wrote:  Guys pleas don't delete the questions this is just dumb, without ˗ˏˋ NYAN CAT ˎˊ we wouldn't have know later on what the question for that solution was.
So pleas don't remove the question or change the title...
There is a reason why there is a option to close a thread.

(Jan 5, 2019 11:41 AM)_CASP3R_ Wrote:  Hey man... Just tried the code. The window still appears.

(Jan 5, 2019 11:49 AM)Abruptum Wrote:  Guys pleas don't delete the questions this is just dumb, without ˗ˏˋ NYAN CAT ˎˊ we wouldn't have know later on what the question for that solution was.
So pleas don't remove the question or change the title...
There is a reason why there is a option to close a thread.

(Jan 5, 2019 11:54 AM)˗ˏˋ NYAN CAT ˎˊ˗ Wrote:  I tried it, the dialog is hidden.

---

Yup I agree with you.

(Jan 5, 2019 11:58 AM)Nick (Name) Wrote:  This is honestly my preferred way of launching other program's with the Process class:

Code

if (new Process
{
   StartInfo =
   {
       FileName = "mstsc",
       Arguments = "/v: 127.0.0.1",
       WindowStyle = ProcessWindowStyle.Hidden
   }
}.Start())
{
   //Process has started
}

(Jan 5, 2019 11:58 AM)_CASP3R_ Wrote:  I mean the rdp window,  I want that hidden not just the connecting window its still appearing on mine. Thanks again for helping.

---

I mean the rdp window, I want that hidden not just the connecting window its still appearing on mine. Thanks for helping.

(Jan 5, 2019 12:03 PM)Nick (Name) Wrote:  Check out the ProcessStartInfo class documentation https://docs.microsoft.com/en-us/dotnet/api/system.diagnostics.processstartinfo