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+---- Thread: [Shell] Bash wait for a command to finish then execute another command (/showthread.php?tid=6046044)
Bash wait for a command to finish then execute another command - friiz1337 - Feb 2, 2020
Hello guys.
I have a problem waiting for a specific command within an infinite loop to finish, so another command in another loop to execute. Also the command that I'm waiting to finish is located in a background loop (&). I tried getting the PID of the mv command and then wait for this process to finish but it didn't work to save it as a global variable with process substitution.
Here is an example code of what is happening:
Code
while true; do
echo "Renaming File"
mv File1 File2
sleep 2
echo "Renaming File again"
mv File2 File1
done &
while true; do
wait for the mv File2 File1 command to finish
execute another command
doneRE: Bash wait for a command to finish then execute another command - FantaŠec - Feb 3, 2020
The bash script executes sequentially, not in parallel. The functionality you are looking for already exists without special logic you need to create. If you can provide more background on the goal/intent I can help a bit more; however, in what is shown already, bash will execute the Mv command and wait for completion or error before moving on to next line (unless you force bash to not do this using & or other methods).
RE: Bash wait for a command to finish then execute another command - sed-i - May 14, 2020
Code
LOOP1 () {
while true; do
echo "Renaming File"
mv $OLD $NEW
if [ $? -eq 0 ]; then
echo "Renaming File again"
mv $NEW $OLD
if [ $? -eq 0 ]; then
echo "execute another command"
fi
else
echo FAIL
fi
done
}
LOOP2 () {
while true; do
echo "Renaming File"
mv $OLD $NEW
if [ $? -eq 0 ]; then
echo "Renaming File again"
mv $NEW $OLD
TMPVAL=$?
echo "do something else before running the 'execute another command'"
if [ $TMPVAL -eq 0 ]; then
echo "execute another command"
fi
else
echo FAIL
fi
done
}old post lol, but prbly very simple.