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+---- Thread: Steganography & Cryptography Challenge HackForums #5 (/showthread.php?tid=6115727)
Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
Dear HF
Welcome to the Steganography & Cryptography Challenge #5
With the information provided below,
please find the final message and PM it to me.
I will post every winner on a list below.
Post below to let me know you are trying to solve the puzzle.
There is NO prize, this is purely for fun and educational purposes.
I hope that you will have some fun! Good luck and good hunt!
please find the final message and PM it to me.
I will post every winner on a list below.
Post below to let me know you are trying to solve the puzzle.
There is NO prize, this is purely for fun and educational purposes.
I hope that you will have some fun! Good luck and good hunt!
PHP Code
<?php
Здравствуйте, ваше путешествие начинается здесь. Расшифруйте следующий текст. Это приведет вас к успеху. Это принесет вам счастье в жизни. Найдите зашифрованное сообщение и претендуйте на трон.
01101000 01110100 01110100 01110000 01110011 00111010 00101111 00101111 01101001 01100010 01100010 00101110 01100011 01101111 00101111 01111001 00110101 01100111 01001100 00111001 00111000 00111001
^If this is posted in the wrong section, please let me know.
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
eh I can't be bothered doing the ottendorf but I'll try.
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:06 PM)Mr. Robot Wrote: eh I can't be bothered doing the ottendorf but I'll try.
AHahah please, you will have to crack this one man, I corrected some things from last time!
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
(Oct 14, 2020 05:07 PM)Дождь Wrote: AHahah please, you will have to crack this one man, I corrected some things from last time!
Well what a waste of time that was - I literally went through and did the first number as page number in roman numerals thinking you were going to try one up me.
RIP.
are so numerous, the shades of meaning conveyed
nical terms to convey the doctrines and conceptions
Sebastian with his juvenile and faultless figure might
according to circumstances likely only to mislead and
often must be employed in default of any others in
lar character, there remains one point which is
with one another upon the point. A fair summary of their
short indeed of the expressive force of the original,
my honour' 'egad' 'in heaven's name', which fall
The Greek title of tlie diah^gue is Vop'yia^, rj irepl Jjtjto
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:16 PM)Mr. Robot Wrote: Well what a waste of time that was - I literally went through and did the first number as page number in roman numerals thinking you were going to try one up me.
RIP.
are so numerous, the shades of meaning conveyed
nical terms to convey the doctrines and conceptions
Sebastian with his juvenile and faultless figure might
according to circumstances likely only to mislead and
often must be employed in default of any others in
lar character, there remains one point which is
with one another upon the point. A fair summary of their
short indeed of the expressive force of the original,
my honour' 'egad' 'in heaven's name', which fall
The Greek title of tlie diah^gue is Vop'yia^, rj irepl Jjtjto
Wait, so you did solve it or what happened, it should be clear where to go in this one, when you get to the pages?
But this has to be easy for now, there will be a day, where I will one up you with something surprising! :D
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
// Anywho I cbf doing it because 11|8|3 should be the following line:
ago. Hardest of all is the task of doing justice to
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:19 PM)Mr. Robot Wrote: // Anywho I cbf doing it because 11|8|3 should be the following line:
ago. Hardest of all is the task of doing justice to
I take it as you manage to almost solve it? Man, do the task and be the first one to solve it :D
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
(Oct 14, 2020 05:21 PM)Дождь Wrote: I take it as you manage to almost solve it? Man, do the task and be the first one to solve it :D
Well as I said according to how it should work - the first two letters should be "ao" but no 3 letter word would start with that so it must be setup different than page|line|letter
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:22 PM)Mr. Robot Wrote: Well as I said according to how it should work - the first two letters should be "ao" but no 3 letter word would start with that so it must be setup different than page|line|letter
I think you might be looking at page number wrong - Try to look at it differently
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
(Oct 14, 2020 05:33 PM)Дождь Wrote: I think you might be looking at page number wrong - Try to look at it differently
Yeah I looked both at the PDF page number listed as you scroll down as well as the roman numeral page number.
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:33 PM)Mr. Robot Wrote: Yeah I looked both at the PDF page number listed as you scroll down as well as the roman numeral page number.
So are you taking x / 248 pages when you do it?
RE: Steganography & Cryptography Challenge HackForums #5 - Mr. Robot - Oct 14, 2020
(Oct 14, 2020 05:36 PM)Дождь Wrote: So are you taking x / 248 pages when you do it?
Yup.
I'll let someone else do it, i'm assuming it's the final step but apparently I can't count.
Unless the first word is an anagram for "ago" - from what I see it works out to "aog"
RE: Steganography & Cryptography Challenge HackForums #5 - Blockonome - Oct 14, 2020
(Oct 14, 2020 05:36 PM)Mr. Robot Wrote: Yup.
I'll let someone else do it, i'm assuming it's the final step but apparently I can't count.
I sent you a PM, the thread is updated, I will also double check the solution myself now :D