(May 8, 2013 08:44 PM)Area 51 Wrote: what is the difference between ac generator and dc generator?
DC Generators produce a direct current, one that travels in one direction through the circuit, kind of like a race car on a track.
AC Generators produce an alternating current, which changes its direction many times per second. It's a bit harder to picture, but you can almost thing of it as a person going back and forth on a swing.
(May 8, 2013 09:03 PM)Feynman Wrote: DC Generators produce a direct current, one that travels in one direction through the circuit, kind of like a race car on a track.
AC Generators produce an alternating current, which changes its direction many times per second. It's a bit harder to picture, but you can almost thing of it as a person going back and forth on a swing.
Oh wow, and yea it is pretty difficult to picture. :S
(May 8, 2013 09:41 PM)Area 51 Wrote: Oh wow, and yea it is pretty difficult to picture. :S
Here's a better analogy I found:
Imagine you have a series of pipes, connected together into a loop. The pipes are filled with water, which is being pumped through the pipes in one direction. After a certain amount of time, the pump reverses, pushing the water in the opposite direction. Here's a diagram I made to help you:
(May 8, 2013 10:00 PM)Feynman Wrote: Here's a better analogy I found:
Imagine you have a series of pipes, connected together into a loop. The pipes are filled with water, which is being pumped through the pipes in one direction. After a certain amount of time, the pump reverses, pushing the water in the opposite direction. Here's a diagram I made to help you:
![[Image: onYUrXe.png]](https://i.imgur.com/onYUrXe.png)
Thank you so much sir . Appreciate your help :)🎉
Why is electricity transmitted using AC currents and not DC currents ??? Please help me out with this
May 21, 2013 06:55 PM
(This post was last modified: May 21, 2013 07:12 PM by Feynman.)
(May 21, 2013 06:50 PM)Area 51 Wrote: Why is electricity transmitted using AC currents and not DC currents ??? Please help me out with this
There are a few advantages to AC current versus DC.
1) AC can travel through long circuits for efficiently
2) AC also allows for high voltages to be used more easily. With an AC circuit, you can use a transformer to easily amplify the voltage, but transformers don't work very well with DC.
(May 21, 2013 06:55 PM)Feynman Wrote: There are a few advantages to AC current versus DC.
1) AC can travel through long circuits for efficiently
2) AC also allows for high voltages to be used more easily. With an AC circuit, you can use a transformer to easily amplify the voltage, but transformers don't work with DC. Alright, appreciate your help a lot man, thanks!
Vouch for Feynman. He's very skilled in what he does. If you have any issue, he will be more than glad to assist you with it.
Good luck, man.
Physics help please!
Ross in his Bugatti Veyron Super Sport rolls across a starting line at 25 mph. ¼ mile later he is going 248mph. This takes him 9 seconds. What is his average acceleration in Meters per second? There are 1.1 yards in 1 meter and 1769 yards in 1 mile. Show all of your work
First, convert his initial and final speeds into m/s:
25 miles per hour 1769 yards/mile 1/1.1 meters/yard *1hour/3600s = 11.2 m/s
248 miles per hour = 111 m/s
Now, use the following equation: v_final = v_initial + a*t → a = (v_final-v_initial)/time = (111m/s - 11.2 m/s)/9s = (100m/s)/9s = 11.1 m/s²
Jun 1, 2013 09:57 PM
(This post was last modified: Jun 1, 2013 09:57 PM by Cryptic™.)
My teacher told me cos60 was wrong.
Maybe I drew the diagram wrong?
Here is my work: https://i.imgur.com/9a2o3GS.jpg
Please let me know if I am doing something wrong.
The correct answer is
|R| = 100^2 + 500^2 - 2(100)(500) cos120
But I do not know where the 120 comes from.
Then it's
sinx/500 = sin120/sin576.8
(Jun 1, 2013 09:57 PM)Cryptic™ Wrote: My teacher told me cos60 was wrong.
Maybe I drew the diagram wrong?
Here is my work: https://i.imgur.com/9a2o3GS.jpg
Please let me know if I am doing something wrong.
The correct answer is
|R| = 100^2 + 500^2 - 2(100)(500) cos120
But I do not know where the 120 comes from.
Then it's
sinx/500 = sin120/sin576.8
Usually we measure angles with respect to the x-axis. Given your drawing of 30° CCW from the positive y-axis, plus the 90° from the first quadrant, adding them together we get 120°. I'm not sure if that's the correct way of doing it (I haven't done a question like this in almost 7 years), but that gives you the 120° you were looking for.
DO NOT DEAL WITH THIS MEMBER
Jun 1, 2013 10:45 PM
(This post was last modified: Jun 1, 2013 10:48 PM by Wish..)
Mind integrating this?
integrate 2/(e^(2x))+sqrt (x)
there is no limit btw!
and integrate e^x/(6-e^x)
(Jun 1, 2013 10:45 PM)Wish. Wrote: Mind integrating this?
integrate 2/(e^(2x))+sqrt (x)
there is no limit btw!
Is that ![[Image: sHtzdM3.png]](https://i.imgur.com/sHtzdM3.png) or ![[Image: Tj5kfg4.png]](https://i.imgur.com/Tj5kfg4.png) ?
DO NOT DEAL WITH THIS MEMBER
(Jun 1, 2013 10:48 PM)Feynman Wrote: Is that or ?
the first one. Yeah.
thanks C: mind explaining too if possible
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