[pureacca]

Im trying to read a file and then pass the values through my variables

String name = in.next();
String age = in.nextInt();
String[] friends =in.next();

Person aP = new Person(name, age, friends);
print blah blah
return aP

Any help is appreciated

[StayTech666]

You can't declare an array of strings like that. You'll have to initialize the array first and then add the values you read in.

String[] friends = new String[20];

[TheNaked]

https://www.youtube.com/watch?v=nP_kYxxhaX4

[SIM-429621]

You can't just assign string to an array of strings like that, you can either do this:

Code

String[] friends = new String[size_of_your_array];
friends[0] = in.next();

or do like you did but use ".split()" method on the user input as ".split()" will split the string by the delimiter you specify and return an array of strings.

[Owl]

How are you formatting your storage?

[pureacca]

I solved it by created 3 sub friends and parsing each of what they read into it. probably an awful solution.
i did string friend1 = in.next; string friend2 = in.next; string friend3 = in.next;
String[] friends = {friend1,friend2,friend3};

[Sheeple]

I solved it by created 3 sub friends and parsing each of what they read into it. probably an awful solution.
i did string friend1 = in.next; string friend2 = in.next; string friend3 = in.next;
String[] friends = {friend1,friend2,friend3};

Easier with a loop and friends[i] = in.next()

[SIM-429621]

Easier with a loop and friends[i] = in.next()

Considering it's only 3 strings, it would be pretty much the same.

[ComplexEternity]

Im trying to read a file and then pass the values through my variables

String name = in.next();
String age = in.nextInt();
String[] friends =in.next();

Person aP = new Person(name, age, friends);
print blah blah
return aP

Any help is appreciated

1. - I am assuming this is not full code, but ensure that your 'Person' class has the proper constructor types.
2. - Arrays should be declared in this format:

Code

String[] myStringArr = new String[size_of_array];

So you would do something like:

Code

//Let's say you are taking in 3 friends...
String[] friends = new String[3];
for(int i = 0; i < 3; i++) {
     friends[i] = in.next(); // take in next String and put it in the Array
}

[jp78]

1. - I am assuming this is not full code, but ensure that your 'Person' class has the proper constructor types.
2. - Arrays should be declared in this format:

Code

String[] myStringArr = new String[size_of_array];

So you would do something like:

Code

//Let's say you are taking in 3 friends...
String[] friends = new String[3];
for(int i = 0; i < 3; i++) {
     friends[i] = in.next(); // take in next String and put it in the Array
}

Uhm he said he is having trouble with the String array, not the constructor. 2, thats basically a repost of what everyone said. Three, Lists are amazing. (List<?>)

[ComplexEternity]

Uhm he said he is having trouble with the String array, not the constructor. 2, thats basically a repost of what everyone said. Three, Lists are amazing. (List<?>)

Excuse me, but I gave a solution to the String array problem. And no, I did not repost what everyone said, I gave my own solution (which is similar to everyone else's and there is no problem to that)