[The Real Slim Shaddy]

I need this small code to save the user input on a website into mysql database pls help

[-VeX-]

PHP Code


<?php 
mysql_query("INSERT INTO table VALUES (*your vablues here*)") 


simple as that!

[Gene]

You will also need the connect function that will let you connect to the MySQL database, I suggest you read here: http://www.tizag.com/mysqlTutorial/mysqlinsert.php

[The Real Slim Shaddy]

PHP Code


<?php 
mysql_query("INSERT INTO table VALUES (*your vablues here*)") 


simple as that!

I have done this :

Code

<?php
$Name = $_POST['Name'];
$Country = $_POST['Country'];
$Cell = $_POST['Cell'];
$Service = $_POST['Service'];
$Email = $_POST['Email']

mysql_connect("localhost","my_admin","my_password") or die('Error: '. mysql_error());
mysql_select_db("uh1_site");

$query="INSERT INTO tester(Name,Country,Cell,Service,Email)VALUES('".$Name."', '".$Country."', '".Cell."', '".Email."')";

?>

query not generating any error but data is not inserted

[document.write]

It needs to be

PHP Code


<?php 
// It needs the mysql_query() function to work. you can't just use a variable named query.
$query=mysql_query("INSERT INTO tester(Name,Country,Cell,Service,Email)VALUES('".$Name."', '".$Country."', '".Cell."', '".Email."')"); 


[-VeX-]

change

this:

PHP Code


<?php 
$query="INSERT INTO tester(Name,Country,Cell,Service,Email)VALUES('".$Name."', '".$Country."', '".Cell."', '".Email."')"; 


into:

PHP Code


<?php 
$query= mysql_query("INSERT INTO tester(Name,Country,Cell,Service,Email)VALUES('".$Name."', '".$Country."', '".Cell."', '".Email."')"); 


[Kisuke]

I have done this :

Code

<?php
$Name = $_POST['Name'];
$Country = $_POST['Country'];
$Cell = $_POST['Cell'];
$Service = $_POST['Service'];
$Email = $_POST['Email']

mysql_connect("localhost","my_admin","my_password") or die('Error: '. mysql_error());
mysql_select_db("uh1_site");

$query="INSERT INTO tester(Name,Country,Cell,Service,Email)VALUES('".$Name."', '".$Country."', '".Cell."', '".Email."')";

?>

query not generating any error but data is not inserted

I'm sorry but your code is terribly wrong, your submitting the query wrong. I just wrote this up quick for you.

Code

$Host = "localhost"; // Do NOT change unless specified by your host
$SQL_Username = " " // Your mysql db username
$SQL_Password = " " // Your mysql db password
$db_name = " " // your mysql database name

$Connection = mysql_connect($Host, $SQL_Username, $SQL_Password) or die(mysql_error()); // Creates a Connection to the mysql database
mysql_select_db($db_name, $Connection) or die(mysql_error()); // Selects the MySQL Database to be used

$query = mysql_query("INSERT INTO tablename(Column_1, Column_2, Column_3)VALUES('value1', 'value2', 'value3')") or die(mysql_error()); // Processes MySQL Query

[The Real Slim Shaddy]

I have used this code now :

PHP Code


<?
$Host = "localhost"; // Do NOT change unless specified by your host
$SQL_Username = "username" // Your mysql db username
$SQL_Password = "password" // Your mysql db password
$db_name = "db_name" // your mysql database name

$Connection = mysql_connect($Host, $SQL_Username, $SQL_Password) or die(mysql_error()); // Creates a Connection to the mysql database
mysql_select_db($db_name, $Connection) or die(mysql_error()); // Selects the MySQL Database to be used

$query = mysql_query("INSERT INTO tablename(Name,Country,Cell,Service,Email)VALUES('$_POST[Name]','$_POST[Country]','$_POST[Cell]','$_POST[Email]')") or die(mysql_error()); // Processes MySQL Query

?>

and getting this erro

Parse error: syntax error, unexpected T_VARIABLE in /home/uh1/public_html/post.php on line 4

[Uncomplicated]

@ Shaddy, variable declarations are incorrect, you can fix that.

[blackstrider]

I have used this code now :

PHP Code


<?
$Host = "localhost"; // Do NOT change unless specified by your host
$SQL_Username = "username" // Your mysql db username
$SQL_Password = "password" // Your mysql db password
$db_name = "db_name" // your mysql database name 


Check your original source code starting line 4. You should terminate the variables properly with a semicolon.

[The Real Slim Shaddy]

OK now everything looks fine just one error that is :

Code

Column count doesn't match value count at row 1

[KeepSafe]

Thats because you are addressing 5 columns but only allocating values to four. if you have only 4 values then you need to add a NULL value in there somewhere.
You may also want to add some security to the script. It's massively exploitable.
Just add

PHP Code


<?php 
mysql_real_escape_string($_POST['value goes here']) 


To your script for each value.
That will make it a bit better.

[The Real Slim Shaddy]

YES YES YES YES YES YES YES DONE THANK YOU GUYS !!!