[SwagDogger]

So I'm EXTREMELY new to C++, and have just started learning it about 2 days ago.
I'm trying to make a very basic calculator, and this is what I've got.

Code

#include <iostream>
using namespace std;

int main()
{
    int firstnumber;
    int secondnumber;
    string check;
    string operation;

    cout << "Enter your first number: \n";
    cin >> firstnumber;

    cout << "Enter your second number: \n";
    cin >> secondnumber;

    cout << "NOTE: Your numbers will not show decimals, because they will be rounded. \n";

    cout << "Enter your operation. Enter +,-,*, or /. \n";
    cin >> operation;
    if(operation == "+"){
        cout << firstnumber << " added with " << secondnumber << " is equal to " << (firstnumber + secondnumber) << ". \n";
    }
    else if(operation == "-"){
        cout << secondnumber << " subtracted from " << firstnumber << " is equal to " << (firstnumber - secondnumber) << ". \n";
    }
    else if(operation == "*"){
        cout << firstnumber << " multiplied with " << secondnumber << " is equal to " << (firstnumber * secondnumber) << ". \n";
    }
    else if(operation == "/"){
            cout << firstnumber << " divided by " << secondnumber << " is equal to " << (firstnumber / secondnumber) << ". \n";
    }
    else if(operation != "+" or "-" or "*" or "/"){
        cout << "You have entered an unrecognized operation. \n";
    };
    cout << "Would you like to complete another calculation? [yes or no.] \n";
    cin >> check;
    if(check == "yes"){
        cout << "You picked yes. \n";
        [b]RESTART PROGRAM[/b]
    }
    else if(check == "no"){
        cout << "You picked no. \n";
        [b]CLOSE PROGRAM[/b]
    }
    else if (check != "yes" or "no"){
        cout << "You have entered something unrecognized. \n";
    }

}

Any help for this?

[0xDEAD10CC]

How about instead of "restarting" the program, you just loop the code that you have? Investigate a while loop, or probably even better depending on how you implement it... A do-while loop.

[Canonsx130]

Loop the entire calc operations in a do-while loop. Also instead of several else if conditions, try using a switch statement instead.

[GalileoGalilei]

I agree with Canonsx130, better using switch statement, also try using different variables.

Code

double a, b, answer;
char operation;

    std::cin >> a >> operation >> b;
    switch (operation)
    {
        case '-':
            answer = a - b;
            std::cout << "answer: " << answer << std::endl;
            break;
        case '+':
            answer = a + b;
            std::cout << "answer: " << answer << std::endl;
            break;
        case '*':
            answer = a * b;
            std::cout << "answer: " << answer << std::endl;
            break;
        case '/':
            answer = a / b;
            std::cout << "answer: " << answer << std::endl;
            break;
    }

[Nuclear3mbargo]

Simply:
1. Create a boolean(bool) variable on the top of the main function

Code

int main(){
    bool continue_looping = true;
    //code...
    return 0;
}

2. Enter all the other code in a while loop, which will continue until the variable continue_looping is set equal to false

Code

int main(){
    bool continue_looping = true;
    while(continue_looping){
        //code..
    }
    return 0;
}

3. if the user don't want to another calculation, set continue_looping to false, else do nothing:

Code

int main(){
   bool continue_looping = true;
   while(continue_looping){
        //code..
        cout << "Would you like to complete another calculation? [yes or no.] \n";
        cin >> check;
        if(check == "yes"){
            cout << "You picked yes. \n";
        }
        else if(check == "no"){
            cout << "You picked no. \n";
            continue_looping = false;
        }
        else if (check != "yes" || check != "no"){
            cout << "You have entered something unrecognized. \n";
        }
   }
   return 0;
}

my recommendation: If the user enters something unrecognized, ask him for input again, you can do this by another while loop, before asking him for input, which will loop until you break it, you can do the same when you're asking about the operator. here is the code:

Code

int main(){
   bool continue_looping = true;
   while(continue_looping){
        //code..
        while(true){
            cout << "Would you like to complete another calculation? [yes or no.] \n";
            cin >> check;
            if(check == "yes"){
                cout << "You picked yes. \n";
                break;
            }
            else if(check == "no"){
                cout << "You picked no. \n";
                continue_looping = false;
                break;
            }
            else if (check != "yes" || check != "no"){
                cout << "You have entered something unrecognized. \n";
            }
        }
   }
   return 0;
}

Here is the total code

Code

int main()
{
    bool continue_looping = true;
    while(continue_looping){
      int firstnumber;
      int secondnumber;
      string check;
      string operation;

      cout << "Enter your first number: \n";
      cin >> firstnumber;

      cout << "Enter your second number: \n";
      cin >> secondnumber;

      cout << "NOTE: Your numbers will not show decimals, because they will be rounded. \n";

      while(true){
      cout << "Enter your operation. Enter +,-,*, or /. \n";
      cin >> operation;
      if(operation == "+"){
            cout << firstnumber << " added with " << secondnumber << " is equal to " << (firstnumber + secondnumber) << ". \n";
            break;
      }
      else if(operation == "-"){
            cout << secondnumber << " subtracted from " << firstnumber << " is equal to " << (firstnumber - secondnumber) << ". \n";
            break;
      }
      else if(operation == "*"){
            cout << firstnumber << " multiplied with " << secondnumber << " is equal to " << (firstnumber * secondnumber) << ". \n";
            break;
      }
      else if(operation == "/"){
      cout << firstnumber << " divided by " << secondnumber << " is equal to " << (firstnumber / secondnumber) << ". \n";
      break;
      }
      else if(operation != "+" || "-" || "*" || "/"){
            cout << "You have entered an unrecognized operation. \n";
      }
      }
      while(true){
      cout << "Would you like to complete another calculation? [yes or no.] \n";
      cin >> check;
      if(check == "yes"){
      cout << "You picked yes. \n";
      break;
      }
      else if(check == "no"){
            cout << "You picked no. \n";
            continue_looping = false;
            break;
      }
      else if (check != "yes" or "no"){
            cout << "You have entered something unrecognized. \n";
      }
      }
    }
    return 0;
}

Exercise: If you want to you can do this exercise. Write check for the other inputs(the numbers) and check for illegal arithmetic operations(for example division by zero).
Hint: cin.fail()