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2 Math problems - Unit of Rate

[Image: J9wVpEJ.png]

[Image: CkzQrbL.png]

And if u can tell me how to do it please
So im guess the car is traveling at uniform speed then

A- 26/13=2 so 380/2=190miles
B- 380miles/26gals= 14.61 miles/gallon so 206miles/14.61miles/gallon = 14.1 gallons

distance= rate * time

d- [(15miles/(60)(60))](35s)
(.0042miles/sec)(35sec)
=.14558miles(5280ft/mile)
770ft
(Oct 19, 2016 05:43 PM)psychoflame Wrote:  So im guess the car is traveling at uniform speed then

A- 26/13=2 so 380/2=190miles
B- 380miles/26gals= 14.61 miles/gallon so 206miles/14.61miles/gallon = 14.1 gallons

distance= rate * time

d- [(15miles/(60)(60))](35s)
(.0042miles/sec)(35sec)
=.14558miles(5280ft/mile)
770ft
Excellent! Thank you!


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