[Malentor]

just another code I made practicing, I will now try to read some documentation about the urllib library and try to make some different scripts, until now I only was able to make simple scripts like this one.

PHP Code


<?php 
import random
import time
import sys

for i in "GUESSING GAME CODED BY MALENTOR #3 SCRIPT EVER MADE":
     time.sleep(0.08 )
     sys.stdout.write(i)
     sys.stdout.flush()


level_choice = int(input("""
1 = EASY MODE -> (0 - 10)
2 = MEDIUM MODE -> (0 - 50)
3 = EXPERT MODE -> (0 - 100)
INSERT YOUR MODE: """))

easy = random.randint(0,10)
medium = random.randint(0,50)
expert = random.randint(0,100)

if level_choice == 1:

    while True:
        # CHEATS ON -> print(easy)
        userGuess = int(input("Your guess (0-10): "))
        if userGuess < easy:
            print("The number you entered is LOWER than the random one.")
        elif userGuess > easy:
            print("The number you entered is HIGHER than the random one")
        else:
            print("CONGRATULATIONS, NUMBER HAS BEEN GUESSED")
            break

elif level_choice == 2:
        while True:
            # CHEATS ON -> print(medium)
            userGuess = int(input("Your guess (0-50): "))
            if userGuess < medium:
                print("The number you entered is LOWER than the random one.")
            elif userGuess > medium:
                print("The number you entered is HIGHER than the random one")
            else:
                print("CONGRATULATIONS, NUMBER HAS BEEN GUESSED")
                break

elif level_choice == 3:
        while True:
            # CHEATS ON -> print(expert)
            userGuess = int(input("Your guess (0-100): "))
            if userGuess < expert:
                print("The number you entered is LOWER than the random one.")
            elif userGuess > expert:
                print("The number you entered is HIGHER than the random one")
            else:
                print("CONGRATULATIONS, NUMBER HAS BEEN GUESSED")
                break 


[arkoydas]

Simple and good.Keep working mate.
why are you using sys module: (sys.stdout.write("")) in order to print something?

[TheWarOwl]

Simple and good.Keep working mate.
why are you using sys module: (sys.stdout.write("")) in order to print something?

I believe just to put something into practice. Not necessary but good to learn

[Malentor]

Simple and good.Keep working mate.
why are you using sys module: (sys.stdout.write("")) in order to print something?

hi,

i wanted to print the some text in loading style and I able to do it only using sys.stdout.write+ sys.stdout.flush

[Hapi]

You should try by adding some try/catches just in case the user doesn't enter a integer number.

[Malentor]

You should try by adding some try/catches just in case the user doesn't enter a integer number.

thank you , next codes will be using .try

[Ensky]

Good work for your third ever script man.

You don't need to use if statements for the levels, dictionaries will come in handy for this. If you don't understand anything in the code below, search the documentation. PM me if you still don't get it or post in the Python section, everyone (mostly) is willing to help!

PHP Code


<?php 
import random
import time
import sys

for i in "GUESSING GAME CODED BY MALENTOR #3 SCRIPT EVER MADE":
    time.sleep(0.08)
    sys.stdout.write(i)
    sys.stdout.flush()

# Dictionary to dictate which set of variables you're using when you select a difficulty.
diff = {
    1: {
        'name': 'Easy',
        'max': 10,
    },

    2: {
        'name': 'Medium',
        'max': 50,
    },

    3: {
        'name': 'Expert',
        'max': 100,
    }
}

level = None # Initialise the variable as variables set in a try / except statement only work in that statement.
while True:
    try:
        level = int(input("""
        1 = EASY MODE -> (0 - 10)
        2 = MEDIUM MODE -> (0 - 50)
        3 = EXPERT MODE -> (0 - 100)
        INSERT YOUR MODE: """))

        # Ensuring that the number is 1, 2 or 3
        if(level < 1 or level > 3):
            raise ValueError # Create a value error if it's not, so it runs the block of code below.

        break

    except ValueError:
        # This block will run if they get a ValueError.
        # A VelueError raises when you you try to use the int() function on a string or float(?)
        print('You must enter either: 1, 2 or 3')

number = random.randint(0, diff[level]['max'])

while True:
    userGuess = int(input("Your guess (0-{}): ".format(diff[level]['max'])))
    if userGuess < number:
        print("The number you entered is LOWER than the random one.")
    elif userGuess > number:
        print("The number you entered is HIGHER than the random one")
    else:
        print("CONGRATULATIONS, NUMBER HAS BEEN GUESSED")
        break