[AssistanceDelinquent]

I have no idea on how to do this task with C.

For example: When user enters 12345 this will be stored as a string. I want to gather each digit of user answer and convert/migrate it to all integer arrays element.

So a integer has the size of 5 and 1 would be intarray[0], 2 would be in intarray[1] etc. etc.

My code directly adds the string[i] to intarray[i]. This is incorrect. Can someone provide any insight for a solution of my problem.

[Irritiable]

I have no idea on how to do this task with C.

For example: When user enters 12345 this will be stored as a string. I want to gather each digit of user answer and convert/migrate it to all integer arrays element.

So a integer has the size of 5 and 1 would be intarray[0], 2 would be in intarray[1] etc. etc.

My code directly adds the string[x] to intarray[x]. This is incorrect. Can someone provide any insight for a solution of my problem.

Hello, AssistanceDelinquent.

You need to use scanf() to solve this problem. The reference to the function is hyperlinked.

I do not know what you have so far, nor do I know what your programming requirements are. Here is an example of how to achieve what you're requesting:

Code

#include <stdio.h> /* scanf() */

int main() {
   const int MAX_ARRAY_ELEMENTS = 5;

   int arrayOfInts[MAX_ARRAY_ELEMENTS];

   printf("Please enter 5 digits: ");
   for (int n = 0; n < MAX_ARRAY_ELEMENTS; ++n) {
       scanf("%d", &arrayOfInts[n]);
   }

   printf("\nThe entered data string is: ");
   for (int r = 0; r < MAX_ARRAY_ELEMENTS; ++r) {
       printf("%d", arrayOfInts[r]);
   }

   return 0;
}

I hope this helps.  🙂

[icko1996]

First make sure you validate the string:
- trim / ignore any whitespace
- trim / ignore characters which are not a digit

If the character encoding of the string is ASCII, which is very likely, you can use this trick.

Code

size_t len = strlen(str);
for (int i = 0; i < len; ++i)
{
   array[ i ] = str[ i ] - '0';
}