Hi guys. I'm messing around with file encryption in C. I wrote a small program that will take a file, process it through 3 encryption algorithms and creates a new file with the encrypted output.
My problem is that after the string in the buffer goes through the first algorithm, it is not giving the right output I want.
Output:
P.S. sorry for the messy code, still learning.
My problem is that after the string in the buffer goes through the first algorithm, it is not giving the right output I want.
Output:
PHP Code
<?php
Thequickbrownfoxjumpsoverthelazydog. //buffer
a√L //result of first algorithm
u√L
0╛g
PHP Code
<?php
#include<stdio.h>
#include<string.h>
#define XOR_KEY1 0x2B //nice
#define XOR_KEY2 0x45 //golden rule
int main(int argc, char *argv[]) {
char buff[1024];
char placeHolder;
int len = strlen(buff);
int x;
FILE *sourceFile;
FILE *destFile;
sourceFile = fopen(argv[1], "r");
destFile = fopen("encryptedFile.txt", "a");
while(feof(sourceFile) == 0) {
fgets(buff, sizeof(buff), sourceFile);
puts(buff); //prints initial content of buffer
for(x = 0; buff[x] != '\0'; x++, len--) { //1st obfuscation
placeHolder = buff[len-1];
buff[len-1] = buff[x];
buff[x] = placeHolder;
if(&buff[x] == &buff[len-1] || &buff[x+1] == &buff[len-1]) {
break;
}
}
puts(buff); //prints output of 1st
for(x = 0; buff[x] != '\0'; x++) { //2nd obfuscation
switch(buff[x]) {
case 'a':
buff[x] = 'u';
break;
case 'e':
buff[x] = 'o';
break;
case 'o':
buff[x] = 'e';
break;
case 'u':
buff[x] = 'a';
break;
case 'A':
buff[x] = 'U';
break;
case 'E':
buff[x] = 'O';
break;
case 'O':
buff[x] = 'E';
break;
case 'U':
buff[x] = 'A';
break;
default:
break;
}
}
puts(buff); //prints output of 2nd
for(x = 0; buff[x] != '\0'; x++) { //3rd obfuscation
if(buff[x] == 'O') {
continue;
}
if((x % 2 == 0) && (x != 0)) {
buff[x] = buff[x] ^ XOR_KEY1;
continue;
}
buff[x] = buff[x] ^ XOR_KEY2;
}
puts(buff); //prints output of 3rd
fprintf(destFile, "%s", buff);
}
fclose(sourceFile);
fclose(destFile);
return 0;
}
P.S. sorry for the messy code, still learning.
