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iOS-inspired switch button
gigajew
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Jan 23, 2017 11:13 PM (This post was last modified: Jan 23, 2017 11:14 PM by gigajew.)
Here's my iOS-inspired switch button. Requires the GraphicsExtension.cs written by Arun Reginald Zaheeruddin.

Implemented features:
switchButton1.Enabled = true | false;
switchButton1.Checked = true | false;

Experimental:
Transparent background: switchButton1.TransparentBackgroundFix = true | false;

[Image: rKWcT80.gif]
[Image: txoH26i.gif]

Download SwitchButton.cs here
Download GraphicsExtension.cs here
[Image: Syr3DlV.png]
hfTP54
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Jan 24, 2017 12:11 AM
Cool! Nice work OP just add an animation and shadow and it will look terrific.
PS. Enable double buffering then
gigajew
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Jan 24, 2017 12:13 AM
(Jan 24, 2017 12:11 AM)hfTP54 Wrote:  Cool! Nice work OP just add an animation and shadow and it will look terrific.
PS. Enable double buffering then

Double buffering is disabled because I was testing transparency (and transparency does not like double buffering)

As for animation I have no clue what I'm doing, and the round white switch thing has a little drop shadow
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Narwin
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Jan 24, 2017 05:55 AM
Nice Op, I also drew two similar switches like this in two of my projects maybe I'll release one of them in time.
Keep it up buddy.
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hfTP54
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Jan 24, 2017 10:36 AM
(Jan 24, 2017 12:13 AM)gigajew Wrote:  Double buffering is disabled because I was testing transparency (and transparency does not like double buffering)
Look here: stackoverflow.com/questions/9358500/making-a-control-transparent

(Jan 24, 2017 12:13 AM)gigajew Wrote:  As for animation I have no clue what I'm doing, and the round white switch thing has a little drop shadow
Look here(by me🤝🎉):
hackforums.net/showthread.php?tid=5208432

Just set the beginning and ending x-coord of your circle as beginning and ending value,done.

Just a little more shadow please!
Ninja
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Jan 24, 2017 12:11 PM
(Jan 24, 2017 10:36 AM)hfTP54 Wrote:  Just set the beginning and ending x-coord of your circle as beginning and ending value,done.

Wow. share more of your wisdom, master.
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