[friiz1337]

Hey guys, I'm trying to figure out how to break out of a loop when the user types the correct username. For now my loop continues to give me the same "Try again" output even when the condition is correct. I tried with 2 loops but it didn't work. Any ideas?

Code

if [ "$userResult" == 1 ]
then
echo Enter password:
read password
else
echo Wrong username. Try again:
read username
while [ "$userResult" == 0 ]
do
echo try again:
read username
done
fi

When username is correct the first time:

Code

Enter Username
BOBO
Enter password:

When username is correct the 2nd time:

Code

Enter Username
B
Wrong username. Try again:
BOBO
try again:

[realsunjester]

Code

#!/bin/bash
echo -n "please type your name: "
read name
while [ "$name" != "sunjester" ]
do
        read name
        echo -n "please type your name: "
done

still buggy but have fun.

[friiz1337]

Code

#!/bin/bash
echo -n "please type your name: "
read name
while [ "$name" != "sunjester" ]
do
       read name
       echo -n "please type your name: "
done

still buggy but have fun.

It doesn't work in my case as the username that is being read is either a 1 or a 0 (output from mysql). Basically if the user is found in the database return 1, else 0.

---

It doesn't work in my case as the username that is being read is either a 1 or a 0 (output from mysql). Basically if the user is found in the database return 1, else 0.

Fixed it by using a function that calls the username. If anyone is also interested in knowing how to fix this problem, PM me.