[blackcoder00]

i want to repeat choosing a color until i press n when the program ask me if i want to keep choosing

PHP Code


<?php 
#include <stdio.h>

int main(){
    int color ;
    char rep[10];
    printf(" donner le color 1/red 2/blue 3/green \n");
    scanf("%d",&color);
    do{
    
    switch(color) {
        case 1 : printf("red");
        break;
        case 2 : printf("blue");
        break;
        case 3 : printf("green");
        break;
        default : printf("you didn't chose anything'");
    
    }
    printf("\n do you want to continue chosing ? \n");
    scanf("%s",&rep);
}while(rep == "y");
} 


[HFDone]

somthing like

PHP Code


<?php 
... 


didnt test it

edit - will post code later if i get free time

[Loki123]

Why don't you use an endless loop and exit at a signal then ?

The tricky part is where you'd be assigning a single char to int along with comparing a char to int.. That causes unexpected behavior.

But my "partial" solution would be like this:

PHP Code


<?php 
#include <stdio.h>

int main(int argc, char* argv[])
{
        int color;
        while(1)
        {
                printf("Choose a color: ");
                scanf("%d", &color); // Save the number 

                switch(color)
                { // Print our response 
                        case 1:
                                printf("\nred\n");
                                break;
                        case 2:
                                printf("\nblue\n");
                                break;
                        case 3:
                                printf("\ngreen\n");
                                break;
                }

                // Exit loop on 0 otherwise repeat loop. 
                if(color == 0) break;
        }
} 


Now... If I am understanding what you want to do correctly. But I have no idea what you want to do with char rep[10];


Edit:
A slightly modified version of the code above and made into a do - while loop.

PHP Code


<?php 
#include <stdio.h>

int main(int argc, char* argv[])
{
        int color;
        char rep = 'y';
        do
        {
                printf("Choose a color: ");
                scanf("%d", &color); // Save the number 

                switch(color)
                { // Print our response 
                        case 1:
                                printf("\nred\n");
                                break;
                        case 2:
                                printf("\nblue\n");
                                break;
                        case 3:
                                printf("\ngreen\n");
                                break;
                }

                printf("Keep choosing ? ");
                scanf(" %c", &rep); /* scanf does not skip any leading whitespaces. Having a space in front of %c makes it skip them */

        }
        while(rep != 'n');
} 


[HFDone]

he is learning and practicing scanf
you can use default for other key

PHP Code


<?php 
int color;
   printf(" donner le color 1/red 2/blue 3/green other/exit\n");
   while(1) { 
      scanf("%d", &color);
      switch(color) {
         case 1 : printf("red\n");
            break;
         case 2 : printf("blue\n");
            break;
         case 3 : printf("green\n");
            break;
         default : exit(1);
      }
   } 


[Loki123]

he is learning and practicing scanf
you can use default for other key

PHP Code


<?php 
int color;
   printf(" donner le color 1/red 2/blue 3/green other/exit\n");
   while(1) { 
      scanf("%d", &color);
      switch(color) {
         case 1 : printf("red\n");
            break;
         case 2 : printf("blue\n");
            break;
         case 3 : printf("green\n");
            break;
         default : exit(1);
      }
   } 


He can, yes as showed in my edit with a do - while loop.